Preliminaries
Bilinear Maps
Let G
1, G
2 be two cyclic groups of prime order p. Let P be a generator of G
1. A bilinear map is a map e : G
1 × G
1 → G
2 with the following properties:
-
1)
Bilinearity: for all P, Q ∈ G
1 and a, b ∈ Z
p
, we have e(aP, bQ) → e(P, Q)ab.
-
2)
Non-degeneracy: e(P, P) ≠ 1.
-
3)
Computability: There is an efficient algorithm tocompute e(P, Q) for all P, Q ∈ G
1.
Linear Secret Sharing Scheme (LSSS)
Definition 1 (Linear Secret Sharing Schemes (LSSS) [2,6]) A secret-sharing scheme Π over a set of parties \( \mathcal{P} \) is called linear (over Z
p
) if
-
1)
The shares for each party form a vector over Z
p
.
-
2)
There exists a matrix an M with l rows and n columns called the share-generating matrix for Π. For all i = 1, …, l, te i’th row of M we let the function ρ defined the party labeling row i as ρ(i). When we consider the column vector v = (s, r
2, …, r
n
), where s ∈ Z
p
is the secret to be shared, and r
2, …, r
n
∈ Z
p
are randomly chosen, then Mv is the vector of l shares of the secret s according to Π. The share (Mv)
i
belongs to party ρ(i).
Suppose that Π is an LSSS for the access structure \( \mathbb{A} \). Let \( \mathrm{S}\in \mathbb{A} \) be any authorized set, and let I ⊂ {1, 2, …, l}. Then, there exist constants {ω
i
∈ Z
p
}
i ∈ I
such that, if {λ
i
} are valid shares of any secret s according to Π, then \( {\displaystyle \sum_{i\in I}}{\omega}_i{\lambda}_i=s \). Futhermore, there these constants {ω
i
} can be found in time polynomial in the size of the share-generating matrix M [6].
Decisional Parallel Bilinear Diffie-Hellman Exponent Assumption
Choose a group G
1 of prime order p according to the security parameter. Let a, s, b
1, …, b
q
∈ Z
p
be chosen at random and P ∈ G
1 be a generator of G
1. If an adversary is given \( \overrightarrow{y}= \)
$$ P,sP,aP,\dots, {a}^qP,\kern0.75em ,{a}^{q+2}P,\dots, {a}^{2q}P $$
$$ {\forall}_{1\le j\le q}\ s\cdot {b}_jP,\left(a/{b}_j\right)P,\dots, \left({a}^q/{b}_j\right)P,\kern0.75em ,\left({a}^{q+2}/{b}_j\right)P,\dots, \left({a}^{2q}/{b}_j\right)P $$
$$ {\forall}_{1\le j,k\le q,k\ne j}\ \left(a\cdot s\cdot {b}_k/{b}_j\right)P,\dots, \left({a}^q\cdot s\cdot {b}_k/{b}_j\right)P $$
it must remain hard to distinguish \( e{\left(P,P\right)}^{a^{q+1}}\in {G}_2 \) from a random element in R ∈ G
2.
An algorithm \( \mathcal{A} \) that outputs z ∈ {0, 1} has advantage ϵ in solving decisional q-parallel BDHE in G
1 if
$$ \Big| \Pr \left[\mathcal{A}\left(\overrightarrow{y},T=e{\left(g,g\right)}^{a^{q+1}s}\right)=0\right] $$
$$ - \Pr \left[\mathcal{A}\left(\overrightarrow{y},T=R\right)=0\right]\Big|\ge \epsilon $$
We say that the (decision) q-parallel BDHE assumption holds if no polytime algorithm has a non-negligible advantage in solving the decisional q-parallel BDHE problem [2].
System Model and Definition
Model
There are four entities in the proposed scheme as follows.
User: The user downloads the shared data from Cloud Server.
Data owner: The data owner encrypts the shared data then uploads to Cloud Server.
Authority: The authority manages attributes in the system and publishes the parameters used for encryption. It generates a secret key that user’s attributes are embedded and PRE keys used for re-encryption and updating secret key. The authority is trusted party.
Cloud Server: Cloud Server stores shared data. It re-encrypts encrypted shared data and update secret key by using PRE keys received from the authority. Similar to previous schemes [3,4], we assume Cloud Server to be curious-but-honest. That is, it will honestly execute the tasks assigned by legitimate parties in the system. However, it would like to learn information of encrypted shared data as much as possible.
Algorithm Definition
Our proposed scheme is composed of 8 algorithms: Auth.Setup, DO.Enc, Auth.Ext, U.Dec, Auth.ReKeyGen, C.ReEnc, C.ReKey, C.AddAtt.
Auth.Setup: The setup algorithm takes as input the security parameter and attribute universe description. It outputs the public parameters PK, master secret key MSK and the keys for granting an attribute J.
DO.Enc: The Encryption algorithm takes as input the public parameters PK, an LSSS access structure \( \mathbb{A} \), and a message ℳ. It outputs a ciphertext CT.
Auth.Ext: The key extraction algorithm takes as input the master key MK, and a set of attributes S. It outputs a secret key SK and t
ID
.
U.Dec: The decryption algorithm takes as input a secret key SK for a set S and a ciphertext CT for an access structure \( \mathbb{A} \). If the set of attributes S satisfies the access structure \( \mathbb{A} \), it outputs a message ℳ.
Auth.ReKeyGen: The re-encryption key generation algorithm takes as input the master key MK and a set of attributes γ for update. It outputs the redefined master key MK′, the redefined public parameters PK′, and the PRE (Proxy Re-Encryption) keys rk.
C.ReEnc: The re-encryption algorithm takes as input an attribute y for update, the ciphertext component D
i
and a PRE key list RKL
y
. It outputs the re-encryption ciphertext component \( {D}_i^{\mathit{\hbox{'}}} \).
C.ReKey: The key regeneration algorithm takes as input an attribute w for update, the secret key component K
w
and the PRE key list RKL
w
. It outputs the updated secret key component \( {K}_w^{\hbox{'}} \).
C.GrantAtt: The attribute grant algorithm takes as input an attribute v, the key for granting an attribute J
v
, t
ID
and the PRE key list RKL
v
. It outputs secret key component K
v
and redefines the key for granting an attribute \( {J}_v^{\boldsymbol{\hbox{'}}} \).
Security Definition
We prove that unauthorized users and Cloud Server cannot decrypt ciphertext CT that was encrypted by the proposed scheme. Since we assume Cloud Server is honest, we do not consider active attacks from Cloud Server by colluding with unauthorized or revoked users. We define two attack models and security models as follows.
Attack Model 1
In this model, we assume an attack by unauthorized users. Security in this model is defined with the following game.
-
-Init. The adversary A submits the challenge access structure \( \mathbb{A} \) to the challenger C.
-
-Setup. The challenger C runs setup algorithm and gives the public parameters PK to the adversary A.
-
-Phase1. The adversary can issue following query.
-
Ext query : The adversary A submits a set of attributes S where S does not satisfy the access structure \( \mathbb{A} \) to the challenger. The challenger C gives secret key corresponding S.
-
Add query : The adversary A submits a set of attributes S′ where S ∪ S′ does not satisfy the challenge access structure \( \mathbb{A} \). The challenger C gives the secret key component K
x
corresponding to S′.
-
-Challenge. The adversary A submits two equal length messages M
0, M
1. The challenger flips a random coin b, and encrypts M
b
under \( \mathbb{A} \). The challenger gives ciphertext CT to the adversary A.
-
-Phase2. Phase1 is repeated.
-
-Guess. The adversary A outputs his guess b′ of b.
The advantage of an adversary A in this game is defined as \( \Pr \left[{b}^{\hbox{'}}=b\right]-\frac{1}{2} \).
Definition 2 A ciphertext-policy attribute-based encryption scheme is secure if all polynomial time adversaries have at most a negligible advantage in the above game.
Attack Model 2
In this model, we assume an attack by Cloud Server. Security in this model is defined with the following game.
-
-Init. The adversary A submits the challenge access structure \( \mathbb{A} \) and version number ver* to the challenger C.
-
-Setup. The challenger C runs setup algorithm and gives the public parameters PK and PRE key and the keys for granting an attribute J to the adversary A.
-
-Phase1. The adversary can issue following query.
-
-Challenge. The adversary A submits two equal length messages M
0, M
1. The challenger flips a random coin b, and encrypts M
b
under \( \mathbb{A} \). The challenger gives ciphertext CT to the adversary A.
-
-Phase2. Phase1 is repeated.
-
-Guess. The adversary A outputs his guess b′ of b.
Definition 3 A ciphertext-policy attribute-based encryption scheme is secure if all polynomial time adversaries have at most a negligible advantage in the above game.
Our Scheme
Overview
The proposed scheme is based on Waters’s scheme of CP-ABE [2]. Water’s scheme supports any LSSS access structure. We apply the idea of attribute revocation shown in [3] to the proposed scheme. In the proposed scheme, the attribute key is included in the ciphertext and secret key to delegate attribute revocation processes to Cloud Server. The attribute key is master key components corresponding to each attribute in the system. When user’s attributes are revoked, the authority re-defines the attribute keys, and generates PRE keys for updating the attribute keys. Cloud Server re-encrypts ciphertext and updates secret key by updating attribute key by using PRE key. Each attribute is associated with version number for updating attribute key.
Cloud Server keeps user list UL, re-encryption key list RKL and the key for granting an attribute to secret key J. UL records user’s ID, user’s attribute information, secret key components, t
ID
. t
ID
is a random number that randomize each secret key to prevent users’ collusion attack. t
ID
should “bind” components of one user's key together so that they cannot be combined with another user's key components[2]. RKL records update history of attribute (version number) and PRE keys.
When granting attributes to users, Cloud Server generates user’s secret key components correspond to granting attribute from t
ID
and J, and sends secret key component to the user. The user joins secret key component to own secret key. Thus, it is possible to grant attributes to users without generation of new secret key by the authority.
Algorithm
Auth.Setup(U) The setup algorithm takes as input the number of system attributes U. It first chooses a group G
1 of prime order p, a generator P ∈ G
1. It then chooses random group elements Q
1, …, Q
U
∈ G
1 that are associated with the U attributes in the system. In addition, it chooses two random α, a ∈ Z
p
, and random Att
1, …, Att
U
∈ Z
p
as the attribute key.
The public parameters are
$$ PK:=\kern0.5em <P,e{\left(P,P\right)}^{\alpha },aP,{Q}_1,\dots, {Q}_U,{T}_1=At{t}_1P,\dots, {T}_U> $$
The master key is MK : = < α, Att
1, …, Att
U
>.
The keys for granting an attribute are J : = < {x, J
x
= 1/Att
x
}1 ≤ x ≤ U
>.
DO.Enc (PK, (M, ρ), ℳ) The Encryption algorithm takes as input the public parameters PK, an LSSS access structure (M, ρ), and a message ℳ. The function ρ associates rows of M to attributes. Let M be an l × n matrix. It first chooses a random vector \( \overrightarrow{v}=\left(s,{y}_2,\dots, {y}_n\right)\in {Z}_p \). For i = 1 to l, it computes \( {\lambda}_i:=\overrightarrow{v}\cdot {M}_i \). It then chooses random r
1, …, r
l
∈ Z
p
and outputs the ciphertext
$$ CT: = <C,{C}^{\hbox{'}},\left({C}_1,{D}_1\right),\dots, \left({C}_l,{D}_l\right)>= $$
$$ <Ke{\left(P,P\right)}^{\alpha s},sP,\left({\lambda}_1(aP)-{r}_1{Q}_{\rho (1)},{r}_1{T}_{\rho (1)}\right),\dots, \left({\lambda}_l(aP)-{r}_l{Q}_{\rho (l)},{r}_l{T}_{\rho (l)}\right)> $$
with (M, ρ).
Auth.Ext (MK, S) The key extraction algorithm takes as input the master key MK, and a set of attributes S. It first chooses a random t
ID
∈ Z
p
. It then outputs t
ID
and the secret key
$$ SK:=<K,L,\forall x\in S\ {K}_x>= $$
$$ <\alpha P+{t}_{ID}(aP),{t}_{ID}P,\forall x\in S\ \left({t}_{ID}/At{t}_x\right){Q}_x>. $$
U.Dec (SK, CT) The decryption algorithm takes as input a secret key SK for a set S and a ciphertext CT for access structure (M, ρ). Suppose that S satisfies the access structure and let I be defined as I = {i : ρ(i) ∈ S}. Then, let {ω
i
∈ Z
p
}
i ∈ I
be as set of consistants such that if {λ
i
} are valid shares of the secret s according to M, then \( {\displaystyle \sum_{i\in I}}{\omega}_i{\lambda}_i=s \).
The decryption algorithm first computes
$$ \frac{e\left({C}^{\hbox{'}},K\right)}{{\displaystyle {\prod}_{i\in I}}{\left(e\left({C}_i,L\right)e\left({D}_i,{K}_{\rho (i)}\right)\right)}^{\omega_i}} = $$
$$ \frac{e{\left(P,P\right)}^{\alpha s}e{\left(P,P\right)}^{as{t}_{ID}}}{{\displaystyle {\prod}_{i\in I}}\left(e{\left(P,P\right)}^{ta{\lambda}_i{\omega}_i}\right)} = e{\left(P,P\right)}^{\alpha s}. $$
It can then decrypt the message ℳ = C/e(P, P)αs.
Auth.ReKeyGen(MK, γ) The re-encryption key generation algorithm takes as input the master key MK and a set of attributes γ for update. For each x ∈ γ, it chooses random \( At{t}_x^{\mathit{\hbox{'}}}\in {Z}_p \) as the new attribute key, and computes \( {T}_x^{\hbox{'}}:=At{t}_x^{\hbox{'}}P \), \( r{k}_{x\to {x}^{\boldsymbol{\hbox{'}}}}:=\frac{At{t}_{\boldsymbol{x}}^{\boldsymbol{\hbox{'}}}}{At{t}_{\boldsymbol{x}}} \). It then replaces each Att
x
of the master key component with \( At{t}_x^{\boldsymbol{\hbox{'}}} \), and each T
x
of public parameter with \( {T}_x^{\boldsymbol{\hbox{'}}} \). It outputs the redefined the master key MK ', the redefined public parameters PK ', and the PRE keys rk := {x, rk
x
}
x ∈ γ
.
C.ReEnc(
y(=ρ(i)), D
i
, RKL
y
) The re-encryption algorithm takes as input an attribute y(=ρ(i)) for update, the ciphertext component D
i
and a PRE key list RKL
y
. It first checks version of attribute y. If y has the latest version, it outputs ⊥ and exit. Let \( At{t}_{y^{(n)}} \) be defined as an attribute key of the latest version of attribute y. It computes \( r{k}_{y\leftrightarrow {y}^{(n)}}:=r{k}_{y\leftrightarrow {y}^{\hbox{'}}}\cdot r{k}_{y^{\hbox{'}}\leftrightarrow {y}^{\hbox{'}\hbox{'}}}\cdot \cdot \cdot r{k}_{y^{\left(n-1\right)}\leftrightarrow {y}^{(n)}}=At{t}_{y^{(n)}}/At{t}_y \). Then, it outputs the re-encrypted ciphertext component \( {D}_{\boldsymbol{i}}^{\boldsymbol{\hbox{'}}}:=r{k}_{y\leftrightarrow {y}^{(n)}}\cdot {D}_i=\left(At{t}_{y^{(n)}}/At{t}_y\right) \)
\( \cdot {r}_iAt{t}_yP={r}_iAt{t}_{y^{(n)}}P \)
.
C.ReKey (w, K
w,ID
, RKL
w
) The key regeneration algorithm takes as input an attribute w for update, the secret key component K
w
and the PRE key list RKL
w
. It first checks version of attribute w. If w has the latest version, it outputs ⊥ and exit. Let \( At{t}_{w^{(n)}} \) be defined as the attribute key for the latest version of attribute w. It computes \( r{k}_{w\leftrightarrow {w}^{(n)}}:=r{k}_{w\leftrightarrow {w}^{\hbox{'}}}\cdot r{k}_{w^{\hbox{'}}\leftrightarrow {w}^{\hbox{'}\hbox{'}}}\cdot \cdot \cdot r{k}_{w^{\left(n-1\right)}\leftrightarrow {w}^{(n)}}=At{t}_{w^{(n)}}/At{t}_w \). It then outputs the updated secret key component \( {K}_w^{\hbox{'}}:=r{k}_{w\leftrightarrow {w}^{(n)}}^{-1}\cdot {K}_w=\left(At{t}_w/At{t}_{w^{(n)}}\right)\cdot \left({\boldsymbol{t}}_{\boldsymbol{ID}}/At{t}_w\right){Q}_w=\left({\boldsymbol{t}}_{\boldsymbol{ID}}/At{t}_{w^{(n)}}\right){Q}_w \).
C.GrantAtt (v, J
v
, t
ID
, RKL
v
) The attribute grant algorithm takes as input an attribute v, the key for granting an attribute J
v
, t
ID
and the PRE key list RKL
v
. It first checks version of attribute v. Let \( At{t}_{v^{(n)}} \) be defined as the attribute key for the latest version of attribute v. It first computes \( r{k}_{v\leftrightarrow {v}^{(n)}}:=r{k}_{v\leftrightarrow {v}^{\hbox{'}}}\cdot r{k}_{v^{\hbox{'}}\leftrightarrow {v}^{\hbox{'}\hbox{'}}}\cdot \cdot \cdot r{k}_{v^{\left(n-1\right)}\leftrightarrow {v}^{(n)}}=At{t}_{v^{(n)}}/At{t}_v \). It then outputs secret key component for \( {K}_v:={t}_{\boldsymbol{ID}}\cdot r{k}_{v\leftrightarrow {v}^{(n)}}^{-1}\cdot {J}_v= \)
\( {t}_{ID}\cdot \left(At{t}_v/At{t}_{v^{(n)}}\right)\cdot \left(1/At{t}_v\right){Q}_v=\left({t}_{ID}/At{t}_{v^{(n)}}\right){Q}_v \) and redefines the key for granting an attribute \( {J}_{\boldsymbol{v}}^{\boldsymbol{\hbox{'}}}:=r{k}_{v\leftrightarrow {v}^{(n)}}^{-1}\cdot {J}_v=\left(1/At{t}_{v^{(n)}}\right){Q}_v \).
We show the flow of our scheme in Fig 1. In Fig 1, γ denotes a set of user u’s attributes which are revoked and β denotes a set of attributes that granting to user u.
Security Proof
We prove that unauthorized users and Cloud Server cannot decrypt ciphertext CT that was encrypted by using the proposed scheme.
Security Proof in the Attack Model 1
Theorem 1 Suppose the decisional q-parallel BDHE assumption holds and a challenge matrix of size is l* × n* where l* × n* ≤ q, our scheme is IND-CPA secure in the attack model 1.
Proof Suppose we have adversary A with non-negligible advantage ϵ against our scheme in the attack model 1. Moreover, suppose it chooses a challenge matrix M* where both dimensions are at most q. We show how to build a simulator, B, that plays the decisional q-parallel BDHE problem.
Init. The simulator takes in a q-parallel BDHE challenge \( \overrightarrow{y},T \). The adversary gives the simulator B the challenge access structure (M*, ρ*), where M* has n* columns.
Setup. The simulator B generates the public parameter PK as follows. The simulator B chooses random α′ ∈ Z
p
and implicitly sets α = α′ + a
q + 1 by letting \( e{\left(P,P\right)}^{\alpha }=e\left(aP,{a}^qP\right)e{\left(P,P\right)}^{\alpha^{\hbox{'}}} \). It outputs public parameter Q
1, …, Q
U
as follows.
-
1.
For each x for 1 ≤ x ≤ U begin by choosing a random value z
x
-
2.
Let X denote the set of indices i, such that ρ*(i) = x.
-
3.
The simulator B computes \( {Q}_x={z}_xP+{\displaystyle {\sum}_{i\in X}}\left\{\left({a}^2{M}_{i,1}^{*}/{b}_i\right)P+\left({a}^2{M}_{i,2}^{*}/{b}_i\right)P+\cdot \cdot \cdot +\left({a}^{n^{*}}{M}_{i,{n}^{*}}^{*}/{b}_i\right)P\right\} \)
Note that if X = ∅ then we have \( {Q}_x={g}^{z_x} \). Also note that the parameters are distributed randomly due to \( {g}^{z_x} \). The simulator B randomly chooses attribute keys t
x
∈ Z
p
for 1 ≤ x ≤ U and computes public parameters Τ
x
= t
x
P. It gives the adversary A the public parameters PK := (P, e(P, P)α, aP, Q
1, …, Q
U
, T
1, …, T
U
).
Phase1. The adversary A issues following queries:
Ext query : The adversary A submits a set of attributes S where S does not satisfy the access structure M* to the challenger. The simulator first chooses a random r ∈ Z
p
. Then it finds a vector \( \overrightarrow{w}=\left({w}_1,\dots, {w}_{n^{*}}\right)\in {Z}_p^{n^{*}} \) such that w
1 = − 1 and for all i where ρ(i) ∈ S ' we have that \( \overrightarrow{w}\cdot {M}_i^{*}=0 \). The simulator B begins by implicitly defining t
ID
as
$$ r+{w}_1{a}^q+{w}_2{a}^{q-1}+\cdots +{w}_{n^{*}}{a}^{q-{n}^{*}+1} $$
It performs this by setting \( L=rP+{\displaystyle {\sum}_{i=2,\dots, {n}^{*}}}{w}_i\left({a}^{q+1-i}P\right) \) = t
ID
P. The simulator can compute K as
$$ {\alpha}^{\hbox{'}}P+arP+\kern1em {\displaystyle \sum_{i=2,\dots, {n}^{*}}}{w}_i\left({a}^{q+2-i}P\right) $$
The simulator B computes K
x
∀
x
∈ S as follows.
Case 1. If there is no i such that ρ*(i) = x, it computes K
x
= (1/t
x
) ⋅ z
x
L.
Case 2. If there is i such that ρ*(i) = x.
-
1)
Let X be the set of all i such that ρ*(i) = x.
-
2)
It computes K
x
as
$$ {z}_xL+{\displaystyle \sum_{i\in X}}{\displaystyle \sum_{j=1,\dots, {n}^{*}}}{M}_{i,j}^{*}\left[\left({a}^j/{b}_i\right)rP+{\displaystyle \sum_{\begin{array}{c}\hfill k=1,\dots, {n}^{*}\hfill \\ {}\hfill k\ne j\hfill \end{array}}}{w}_k\left\{\left({a}^{q+1+j-k}/{b}^i\right)P\right\}\right] $$
-
3)
It calculates \( {K}_x=\left(1/{t}_x\right){K}_x^{\hbox{'}} \).
It gives the adversary A secret key SK := (K, L, ∀ x ∈ S K
x
).
Add query : The adversary A submits a set of attributes S′ where S ∪ S′ does not satisfy the challenge access structure M*.The simulator B computes K
x
∀
x
∈ S′ as follows.
Case1. If there is no i such that ρ*(i) = x, it computes K
x
= (1/t
x
) ⋅ z
x
L.
Case2. If there is i such that ρ*(i) = x.
-
1)
Let X be the set of all i such that ρ*(i) = x.
-
2)
It computes \( {K}_x^{\hbox{'}} \) as
$$ {z}_xL+{\displaystyle \sum_{i\in X}}{\displaystyle \sum_{j=1,\dots, {n}^{*}}}{M}_{i,j}^{*}\left[\left({a}^j/{b}_i\right)rP+{\displaystyle \sum_{\begin{array}{c}\hfill k=1,\dots, {n}^{*}\hfill \\ {}\hfill k\ne j\hfill \end{array}}}{w}_k\left\{\left({a}^{q+1+j-k}/{b}^i\right)P\right\}\right] $$
-
3)
It calculates \( {K}_x=\left(1/{t}_x\right){K}_x^{\hbox{'}} \).
It gives the adversary A the secret key component \( {\left\{{K}_x\right\}}_{\forall x\in {S}^{\hbox{'}}} \).
Challenge. The adversary A submits two equal length messages ℳ0, ℳ1. The simulator B flips a random coin b ∈ {0, 1}. It computes C = ℳ
b
T ⋅ e(sP, α ' P), C = sP. It choose random \( {y}_2^{\hbox{'}},\dots, {y}_{n^{*}}^{\hbox{'}}\in {Z}_p \) and the share the secret using the vector \( \overrightarrow{v}=\left(s,sa+{y}_2^{\hbox{'}},s{a}^2+{y}_3^{\hbox{'}},\dots, s{a}^{n-1}+{y}_{n^{*}}^{\hbox{'}}\right)\in {Z}_p^{n^{*}} \). In addition, it choose random values \( {r}_1^{\hbox{'}},\dots, {r}_l^{\hbox{'}}\in {Z}_p \).
For i = 1, …, n*, we define R
i
as the set of all k ≠ i such that ρ*(i) = ρ*(k). The challenge ciphertext components are then generated as
$$ {D}_i=-{r}_i^{\hbox{'}}{T}_{\rho^{*}(i)}-s{b}_i{T}_{\rho^{*}(i)} $$
$$ {C}_i={h}_{\rho^{*}(i)}^{r_i^{\hbox{'}}}+\left\{{\displaystyle \sum_{j=2,\dots, {n}^{*}}}{M}_{i,j}^{*}{y}_j^{\hbox{'}}(aP)\right\}-{z}_{\rho (i)}\left({b}_i\cdot s\right)P+\left\{{\displaystyle \sum_{k\in {R}_i}}{\displaystyle \sum_{j=1,\dots, {n}^{*}}}{M}_{k,j}^{*}\left({a}^j\cdot s\cdot \left({b}_i/{b}_k\right)P\right)\right\} $$
It gives the adversary A the challenge ciphertext \( C{T}^{*}=\left(C,{C}^{\hbox{'}},\left({C}_1,{D}_1\right),\dots, \left({C}_{l^{*}},{D}_{l^{*}}\right)\right) \).
Phase2. Phase 1 is repeated.
Guess. The adversary A will eventually output a guess b′. of b. The simulator then outputs 0 to guess that \( T=e{\left(P,P\right)}^{a^{q+1}s} \) if b′. = b; otherwise, it outputs 1 to indicate that it believes T is a random group element R ∈ G
2.
When T is a tuple the simulator B gives a perfect simulation so we have that
$$ \Pr =\left[\mathrm{B}\left(\overrightarrow{y},T=e{\left(P,P\right)}^{a^{q+1}s}\right)=0\right]=\frac{1}{2}+\epsilon $$
When T is a random group element the message ℳ
b
is completely hidden from the adversary and we have \( \Pr =\left[\mathrm{B}\left(\overrightarrow{y},T=R\right)=0\right]=\frac{1}{2} \). Therefore, the simulator B can play the decisional q-parallel BDHE game with non-negligible advantage.
Security Proof in the Attack Model 2
Theorem 2 Suppose Waters’s scheme [2] is IND-CPA secure, our scheme is also IND-CPA secure in the attack model 2.
Proof Suppose we have adversary A with non-negligible advantage ϵ against our scheme in the attack model 2. Moreover, suppose it chooses a challenge matrix M* where both dimensions are at most q. We prove there is an simulator B which has advantage at least ϵ against Waters’s scheme simulator (Given input, it responds according to algorithms of the Waters’s scheme).
Init. The adversary A submits the challenge access structure (M*, ρ*) where M* has n* columns and version number ver* to the simulator B. The simulator B submits the challenge access structure (M*, ρ*) to the Waters’s scheme simulator.
Setup. The simulator B receives public parameters PK
' := (P, e(P, P)α, aP, Q
1, …, Q
U
) from the Waters’s scheme simulator. It randomly chooses attribute keys t
x
∈ Z
p
for 1 ≤ x ≤ U and computes public parameters Τ
x
= t
x
P. It computes the key for granting an attribute J := {(1/t
1)Q
1, …, (1/t
U
)Q
U
}. Then, the simulator B computes PRE keys and public parameters T
x
for each version as follows. For x (1 ≤ x ≤ U), for 1 ≤ k ≤ ver* − 1, the simulator B randomly chooses PRE keys \( r{k}_{x^{(k)}\to {x}^{\left(k+1\right)}}\in {Z}_p \) and computes public parameters \( {T}_{x^{\left(k+1\right)}}=r{k}_{x^{(k)}\leftrightarrow {x}^{\left(k+1\right)}}{T}_{x^{(k)}} \). (k + 1) and (k) denote the version number of PRE keys and public parameter. The simulator B gives the adversary A the public parameter PK := (P, e(P, P)α, aP, Q
1, …, Q
U
, T
1, …, T
U
), the key for granting an attribute J and all PRE keys.
Phase1. The adversary A issues following queries:
K
x
query : The adversary A submits a set of attributes S for version k, 1 ≤ k ≤ ver* − 1. we denote \( {V}_{x^{(k)}}={\displaystyle \prod_{i=2}^k}r{k}_{x^{\left(i-1\right)}\leftrightarrow {x}^{(i)}} \). The simulator B randomly chooses t
ID
∈ Z
p
and computes \( \forall x\in S\ {K}_x=\left({t}_{ID}/{t}_x \cdot {V}_{x^{(k)}}\right){Q}_x \). It gives the adversary A the secret key components {K
x
}∀ x ∈ S
.
Challenge. The adversary A submits two equal length messages ℳ0, ℳ1, then the simulator B submits them to the Waters’s simulator. The Waters’s simulator flips a random coin b ∈ {0, 1} and computes ciphertest CT′ := (C, C′, (C
1, D
1), …, (C
l
, D
l
)) ← Enc(PK, (M*, ρ*), ℳ
b
). The simulator B receives the ciphertext CT
', then it computes \( CT:=\Big(C,{C}^{\hbox{'}},\left({C}_1,{V}_{\rho {(1)}^{\left(ve{r}^{*}\right)}}{D}_1\right),\dots, \left({C}_l,{V}_{\rho {(l)}^{\left(ve{r}^{*}\right)}}{D}_l\right) \) from the ciphertext CT′. It gives the adversary A the cipertext CT.
Phase2. Phase 1 is repeated.
Guess. The adversary A outputs will eventually output a guess b′ of b. The simulator B outputs b′ as its guess.
The simulation above shows there is a simulator B that has advantage at least ϵ ageinst Waters’s scheme simulator if there is an adversary A that has advantage ϵ against our scheme.
